Question

How do you express the complex number in trigonometric form `2(cos 180° + i sin 180°)`?

Answer 1

The complex number is already in trigonometric form

Explanation:

The trigonometric form of a complex number `a+bi` is `r(costheta+isintheta)` where `r=sqrt(a^2+b^2)` and `theta` satisfies `theta=arccosa"/"r,theta=arcsin b"/"r`