To what temperature does 1.36 L of hydrogen originally at 25.0°C need to be heated in order to bring the volume to 2.5 L?

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Answer 1 · 2018-05-07T20:49:52

#T_2# = ~45.96C

#(V_1/T_1) = (V_2/T_2)#

Plug in your data.

#(1.36/25)# = #(2.5/T_2)#

Cross-multiply.

1.36#T_2# = 62.5

Divide by 1.36 to isolate for #T_2#.

#62.5/1.36# = #T_2#

#T_2# = 45.95588235294C