Question

Two consecutive odd integers have a sum of 128, what are the integers?

Answer 1

`63 " and " 65`

Explanation:

My strategy for doing problems like this is to divide `128` in half, and take the odd integer directly above and below the result. Doing this for `128` yields this:

`128/2=64`

`64-1=63`
`64+1=65`

`63+65=128`

As `63` and `65` are two consecutive odd integers that sum to `128`, this satisfies the problem.

Answer 2

they are `63` and `65`.

Explanation:

since the two numbers are odd, and consecutive, they have a difference of `2`.
suppose the smaller integer of the two `= x`
`128=x+(x+2)`
`=2x+2`

so as to find the smaller odd integer, you need to find the value of `x`:
`128-2=2x+2-2`
`=126=2x`

`126/2=(2x)/2=63`

`x=63`

63 is the smaller number, so the bigger number is `63+2=65`