A rectangle has an area of 8z² - 12z. If its width is 4z, what is its length? What is the perimeter of the rectangle?

1 Answer
May 10, 2018

l=2z-3

P=12z-6

Explanation:

.

A=8z^2-12z

Area of a rectangle is:

A=l*w where l is the length and w is the width.

8z^2-12z=l*w

w=4z

8z^2-12z=4z*l

4z(2z-3)=4z*l

l=(4z(2z-3))/(4z)=2z-3

Perimeter of a rectangle is:

P=2l+2w

P=2(2z-3)+2(4z)=4z-6+8z=12z-6