Write the equation of a circle that has a center of ( 2,-6) and goes through (8,4)?

1 Answer
May 10, 2018

Equation: #(x-2)^2 + (y+6)^2 = (11.661)^2#

Explanation:

Basic Circle Equation:
#(x-k)^2 + (y-h)^2 = r^2#
Where #(k,h)# is the center.

Therefore,
#r = sqrt((8-2)^2 + (4 + 6)^2) #
# r = 11.661#

Equation: #(x-2)^2 + (y+6)^2 = (11.661)^2#