How do you write the equation of a line in point slope form into slope intercept form given # y - 4 = 3/4(x + 8) #?

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Answer 1 · 2018-05-10T23:29:08

#y=3/4x+10#

Let's start by distributing the #3/4# to both terms on the right. Doing this, we get

#y-4=3/4x+(8*3)/4#

#y-4=3/4x+6#

Lastly, we can add #4# to both sides to get

#y=3/4x+10#

This equation is in the familiar slope-intercept form, #y=mx+b# where #m# is the slope, and #b# is the #y#-intercept.

Hope this helps!