Question

How do you find the derivative of `cos(1-2x)^2`?

Answer 1

`4(1-2x)sin(1-2x)^2`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"`

`rArrd/dx(cos(1-2x)^2)`

`=-sin(1-2x)^2xxd/dx((1-2x)^2)`

`=-sin(1-2x)^2xx2(1-2x)xxd/dx(1-2x)`

`=-sin(1-2x)^2xx2(1-2x)xx-2`

`=4(1-2x)sin(1-2x)^2`