How do you evaluate #3\sqrt { 5} + 3\sqrt { 24} - \sqrt { 45}#?

1 Answer
May 11, 2018

Answer: #6sqrt6#

Explanation:

Here,

factors of 24 = 2.2.2.3 = #2^( 2).6#
factors of 45 = 3.3.5 = #3^(2).5#

Now,

= #3sqrt5+3.sqrt(2^(2).6)-sqrt(3^(2).5)#
= #3sqrt5+3.2sqrt6-3sqrt5#
= #6sqrt6# [Since #3sqrt5# is subtracted from #3sqrt5# that results 0]