How do you solve $5 \sqrt{x + 1} = 21$ $5sqrt(x+1)=21$ ?

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How do you solve $5 \sqrt{x + 1} = 21$ $5sqrt(x+1)=21$ ?

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Answer 1 · 2018-05-12T01:09:21

$x = \frac{416}{25}$ $x=416/25$

Explanation:

Solve:

$5 \sqrt{x + 1} = 21$ $5sqrt(x+1)=21$

Square both sides.

$25 (x + 1) = 441$ $25(x+1)=441$

Divide both sides by $25$ $25$

$x + 1 = \frac{441}{25}$ $x+1=441/25$

Subtract $1$ $1$ from both sides.

$x = \frac{441}{25} - 1$ $x=441/25-1$

Multiply $1$ $1$ by $\frac{25}{25}$ $25/25$ to get an equivalent fraction with $25$ $25$ as the denominator.

$x = \frac{441}{25} - 1 \times \frac{25}{25}$ $x=441/25-1xx25/25$

$x = \frac{441}{25} - \frac{25}{25}$ $x=441/25-25/25$

Simplify.

$x = \frac{416}{25}$ $x=416/25$

Answer 2 · 2018-05-12T01:14:08

Answer = 16.64

Explanation:

$5 \sqrt (x + 1) = 21$ $5 √(x+1) =21$

Divide:

$\frac{5 \sqrt x + 1}{5} = \frac{21}{5} or 4.2$ $(5√x+1)/5 = 21/5 or 4.2$

Square (the opposite of square root):

${(\sqrt (x + 1))}^{2} = {4.2}^{2} or 17.64$ $(√(x+1))^2= 4.2^2 or 17.64$

Subtract:

$x + 1 - 1 = 17.64 - 1$ $x+1-1=17.64-1$

$x = 16.64$ $x=16.64$

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2 Answers

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