How do you find the x and y intercepts for #4x-y=2#?

2 Answers
May 13, 2018

(0,-2)

#(1/2,0)#

Explanation:

#4x-y=2#

Put #x=0, y=-2#

Put #y=0, x =1/2#

May 13, 2018

#"x-intercept "=1/2," y-intercept "=-2#

Explanation:

#"to find the intercepts, that is where the graph crosses "#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArr0-y=2rArry=-2larrcolor(red)"y-intercept"#

#y=0rArr4x-0=2rArrx=1/2larrcolor(red)"x-intercept"#
graph{(y-4x+2)((x-0)^2+(y+2)^2-0.04)((x-1/2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}