How do you evaluate #−12 + 16#?

1 Answer
May 13, 2018

4

Explanation:

Note that #color(red)(16)# can and may be written as #color(red)(+12 + 4)#

So #color(green)(-12)color(red)(+16)# is the same as #ubrace(color(green)(-12)color(red)(+12))color(red)(+4)#
# color(white)("ddddddd.ddddddddddddddd") darr #
#color(white)("ddddddddddd.dddddddd.ddd")0color(white)("dd..")+4#

So #-12+16=4#