How do you write #y=(x-2)^2+6#?

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Answer 1 · 2018-05-13T18:28:39

#y=x^2-4x+12#

The section is: Standard polynomial form.

#y=(x-2)^2+6# is vertex form.

#y=color(blue)((x-2))color(green)( (x-2) )+6#

#y=color(green)(color(blue)( x)(x-2 ) color(white)("dd")color(blue)( -2)(x-2 ))+6 #

Notice the way the minus followed the 2color(white)("d")

#y=x^2-2xcolor(white)("ddd")-2x+4+6#

#y=x^2-4x+12#