Question

How do you convert `9=(5x+y)^2-2y+x` into polar form?

Answer 1

`r=9/(r(5costheta+sintheta)^2-2sintheta+costheta)`

Explanation:

For this we will need:
`x=rcostheta`
`y=rsintheta`

Substituting these equations gives us:
`9=(5rcostheta+rsintheta)^2-2rsintheta+rcostheta`

`9=r^2(5costheta+sintheta)^2-2rsintheta+rcostheta`

`9=r(r(5costheta+sintheta)^2-2sintheta+costheta)`

`r=9/(r(5costheta+sintheta)^2-2sintheta+costheta)`