Question

If speed of a body is increased by 1 percent...what is the change in its kinetic energy?

Answer 1

the change in K.E. = 2 %

Explanation:

Let the initial speed is v m/s .

a change of 1% in speed will mean the new velocity

will be = v + 1% of v = v + (1/100)v = v + 0.01 v

so the kinetic energy before the change `E = (1/2) m. v^2`

after the change of speed

the K.E = E' = (1/2).m. { v.(1.01)}^2

= `(1/2) m. v^2(1.02) = E.`(1.02)

therefore the kinetic energy will change by 2%