Question

How do you solve the following system?: `4x-y=-1 , 3x - 2y = 1`

Answer 1

`x=-3/5`, `y= -7/5`

Explanation:

From the first equation, you have `y = 4x+1`. Substitute in the second equation to get

`3x-2y=1 \iff 3x-2(4x+1)=1 \iff 3x-8x-2=1`

So, you have `-5x = 3` and thus `x=-3/5`

Since we knew that `y = 4x+1`, we have

`y = 4(-3/5)+1 = -12/5+1 = -7/5`