How do you evaluate #csc 180 #? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer KillerBunny May 15, 2018 Unidefined. Explanation: Since #csc(x)=1/sin(x)#, you have #csc(180)=1/sin(180)# But since #sin(180)=0#, you can't divide by it, and thus #csc(180)# is not defined. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 5814 views around the world You can reuse this answer Creative Commons License