How do you complete the square for #x^2+8x#?
1 Answer
May 15, 2018
Explanation:
#"since the coefficient of the "x^2" term is 1"#
#"add "(1/2"coefficient of the x-term")^2" to"#
#x^2+8x#
#rArrx^2+8xcolor(red)(+4)^2=x^2+8x+16=(x+4)^2#
