Calculate #DeltaS^Theta# at #25^circC#?
The reaction
#"CH"_(4text[(g)]) + "N"_2""_text[(g)] -> "HCN"_text[(g)] + "NH"_3""_text[(g)]#
At #25^circC# and #1 "atm"# pressure has
#DeltaH^Theta = 164 kJ# #mol^-1# and
#DeltaG^Theta = 159 kJ# #mol^-1# . Calculate
#DeltaS^Theta# at #25 ^circC# .
A) #400 J# #K^-1# #mol^-1#
B) #100 J# #K^-1# #mol^-1#
C) #2 J# #K^-1# #mol^-1#
D) #17 J# #K^-1# #mol^-1#
E) #70 J# #K^-1# #mol^-1#
The reaction
At
A)
B)
C)
D)
E)
2 Answers
May 16, 2018
D.
Explanation:
The equation for Gibbs free energy is given by:
In this case
May 16, 2018
Explanation:
Use this equation
#"ΔG"^@ = "ΔH"^@ - "TΔS"^@#
On rearranging
