Question

What is the standard form of `y= (3x-5)(2x+3)(x+5)`?

Answer 1

`6x^{3}+29x^{2}-20x-75-y=0`

Explanation:

expand the brackets.

Expanding the first two brackets give you:
`y=(6x^{2}-x-15)(x+5)`

Expand the rest of it gives you:
`y=6x^{3}+29x^{2}-20x-75`

take the y to the other side to give the given answer.