How do you find the limit of # (x^2+2x-1)/(3+3x^2)# as x approaches infinity?
1 Answer
May 17, 2018
Explanation:
#"divide terms on numerator/denominator by "x^2#
#=(x^2/x^2+(2x)/x^2-1/x^2)/(3/x^2+(3x^2)/x^2)=(1+2/x-1/x^2)/(3/x^2+3)#
#rArrlim_(xtooo)((x^2+2x-1)/(3+3x^2))#
#=lim_(xtooo)((1+2/x-1/x^2)/(3/x^2+3))#
#=(1+0-0)/(0+3)=1/3#
