Can someone please help with this **logarithms** question?

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1 Answer
Noah G
May 18, 2018

Use properties of logarithms for all of the following.

i) #log_p sqrt(x) = log_p x^(1/2) = 1/2log_p x = 9/2#

ii) #log_p (1/x) = log_p 1 - log_p x = 0 - 9 = -9#

iii) #log_p(xy) = log_p x + log_p y = 9 + 6 = 15#

iv) #log_y x = logx/logy = log_p x/log_p y = 9/6 = 3/2#

Hopefully this helps!

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