How do you graph #y = 10/3x + 5#?
1 Answer
graph{10x/3 + 5 [-10, 10, -5, 5]}
Explanation:
The equation is in the form,
where,
Here,
but, slope = tan
...where,
Now, to find x- intercept, put y = 0
This means that at ant the point (-1.5, 0), you have to draw an angle of 73.3 degrees. this line will represent the given equation.
An Alternative method:
Make a table:
Consider any random 3 values of x, and find the corresponding values of y. Plot these points, and th eline will pass through all these points linearly.
E.g.: I consider 3 cases, x=0, =1,=-1
1] For
2] For
3] For
Once you get these 3 points on your graph, simply draw a line that passes through each one of them.
(You can follow the same 3 steps while assuming any value of y also.)
*Hope this helps :) *