How do you solve #e^(-2x)<=7#?

1 Answer
Binayaka C.
May 18, 2018

Solution: #x >= - 0.973 or x in [-0.973 , oo) #

Explanation:

#e^(-2 x) <= 7 # , taking natural log on both sides we get,

#-2 x ln(e) <= ln(7) or -2 x <= ln (7) [ln (e)=1]# or

# -2 x <= ln (7) or -2 x <= 1.9459 #

# - x <= 1.9459/2 or - x <= 0.973 # or

#x >= - 0.973 #

Solution: #x >= - 0.973 or x in [-0.973 , oo) # [Ans]

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