Question

What is the the vertex of `y = -12x^2 - 4x-5`?

Answer 1

`x = -(-4)/(2(-12)) = -1/6`
`y=-12(-1/6)^2-4(-1/6)-5 = -14/3`

Explanation:

`y=ax^2 + bx +c`
The vertex is the (x, y) value where `x = (-b)/(2a)` and y = the result when you put the x you found into the equation.