How do you divide and simplify #\frac { 4( x + 9) } { 8( x - 4) } \div \frac { 4x } { 8x ( x - 4) }#?

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Answer 1 · 2018-05-20T01:18:27

#x+9#

#(4(x+9))/(8(x-4)) ÷ (4x)/(8x(x-4))#

is the same thing as (you can flip either term) and multiply:

#(4(x+9))/(8(x-4)) * (8x(x-4))/(4x)#

now cancel factors (you can cancel across the multiplication):

the terms #4, 8 and (x-4)# all cancel

#(x+9)/1* x/(x)#

#(x+9)* 1#

#x+9#