How do you solve #-0.15( 40) + 0.6x = 0.3( 40+ x )#?

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Answer 1 · 2018-05-20T02:23:38

#x=60#

#-0.15( 40) + 0.6x = 0.3( 40+ x )#

here is a trick, multiply the whole equation by 100 to get rid of the decimals:

#100(-0.15( 40) + 0.6x = 0.3( 40+ x ))#

#-15( 40) + 60x = 30( 40+ x )#

#-600 + 60x = 1200+ 30x #

#-600 + 30x = 1200 #

#30x = 1800 #

#x=60#