How do you evaluate (1+ 2v ) ( 1- 2v )?

3 Answers
May 20, 2018

Is a notable identity (1+2v)(1-2v)=1-4v^2

May 20, 2018

1 - 4v^2

Explanation:

Tip: Remember this Algebraic Identity called the difference of squares:
(a+b)(a-b) = a^2 - b^2

sub in a = 1, b = 2v

(1+2v)(1-2v) = 1^2 - (2v)^2 = 1 - 4v^2

1-4v^2

Explanation:

(a+b)(a-b) is equal to a^2-b^2
Here, a=1 and b=2v
So plug that in and you get 1^2-2^2v^2
Which is equal to 1-4v^2