If #f(x)=3x^2# and #g(x)=(x-9)/(x+1)#, and #x!=-1#, then what would #f(g(x))# equal? #g(f(x))#? #f^-1(x)#? What would the domain, range and zeroes for #f(x)# be? What would the domain, range and zeroes for #g(x)# be?

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Answer 1 · 2018-05-21T17:46:53

#f(g(x))=3((x-9)/(x+1))^2#
#g(f(x))=(3x^2-9)/(3x^2+1)#
#f^-1(x)=root()(x/3)#

#D_f={x in RR}#, #R_f={f(x) in RR;f(x)>=0}#
#D_g={x in RR;x!=-1}#, #R_g={g(x) in RR;g(x)!=1}#