The function #f# is defined by #f(x)=1-x^2#, #x sub RR#. Show that #f# is NOT one-to-one. Can someone help me please?

The function #f# is defined by #f(x)=1-x^2#, #x sub RR#.
Show that #f# is NOT one-to-one.

1 Answer
May 21, 2018

Shown below

Explanation:

Its many to one

#f(-1) = f(1) = 0 #

Hence there are multiple #x# that gives the same #f(x) #

In a one to one, there is only one #x# for each #f(x) #

Hence this function actually represents many to one, hence not one to one