How to find the general solution of #x dy/dx = xy + y# ?
1 Answer
May 23, 2018
Explanation:
We do a little bit of algebra before integrating to separate the variables:
#x(dy/dx) = y(x +1)#
#dy/(y dx) = (x +1)/x#
#(dy)/y = (x + 1)/x dx#
#lny = int 1 + 1/xdx#
#lny = x + lnx + C#
#y = Ae^(x + lnx)#
#y = Ae^xe^(lnx)#
#y = Axe^x#
Hopefully this helps!