What are the asymptotes of #y=1/(x-2)# and how do you graph the function?

1 Answer
May 23, 2018

Vertical asymptote: #x=2# and horizontal asymptote: # y=0#
Graph - Rectangular hyperbola as below.

Explanation:

#y = 1/(x-2)#

#y# is defined for #x in (-oo,2) uu (2,+oo)#

Consider #lim_(x->2^+) y =+oo#

And #lim_(x->2^-) y =-oo#

Hence, #y# has a vertical asymptote #x=2#

Now, consider #lim_(x->oo) y =0#

Hence, #y# has a horizontal asymptote #y=0#

#y# is a rectangular hyperbola with the graph below.

graph{1/(x-2) [-10, 10, -5, 5]}