A photon of light with wavelength 700 nm has energy E.A photon of light of what wavelength would correspond to energy 2E?

1 Answer
1s2s2p
May 23, 2018

#350"nm"#

Explanation:

#E=(hc)/lambda#, where:

  • #E# = energy of a photon (#J#)
  • #h# = Planck's constant (#~6.63*10^-34# #"Js"#)
  • #c# = speed of light (#~3.00*10^8"ms"^-1#)
  • #lambda# = wavelength of the photon (#"m"#)

#Elambda="constant"#

#E_1lambda_1=E_2lambda_2#

#E_2=2E_1#

#lambda_1=2lambda_2#

#lambda_2=lambda_1/2=(700"nm")/2=350"nm"#

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