What is the perimeter and area of a right triangle with a hypotenuse of 26 and a leg of 24?

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Answer 1 · 2018-05-23T14:52:29

#"Perimeter" = 60# and #"Area" = 120#

Assign the sides #b = 24 and c = 26#

Use the Pythagorean theorem,

#c^2 = a^2 + b^2#

,to find the length of side a:

#a = sqrt(26^2-24^2)#

#a = 10#

The perimeter is:

#"Perimeter" =a +b +c#

#"Perimeter" =10 +24 +26#

#"Perimeter" = 60#

The area is:

#"Area" = 1/2bh#

If we select side b as the base, then side a is the height:

#"Area" = 1/2(24)(10)#

#"Area" = 120#