A charge of $2 C$ is at $(-2 , 4 )$ and a charge of $-1 C$ is at $(-6 ,8 )$ . If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2018-05-24T08:42:35

$5.62*10^8"N"$

$F=(kQ_1Q_2)/r^2$ , where:

$r^2=(Deltax)^2+(Deltay)^2=(8-4)^2+(-6+2)^2=4^2+4^2=32$

$F=(2(8.99*10^9))/32=(8.99*10^9)/16=5.62*10^8"N"$

A charge of 2 C2 C is at (-2 , 4 )(-2 , 4 ) and a charge of -1 C-1 C is at (-6 ,8 ) (-6 ,8 ) . If both coordinates are in meters, what is the force between the charges?