Question

How do you solve `3x^2+5x-2=0` by factoring?

Answer 1

x1=-4/6 and x2=-1

Explanation:

we need the mathematical formula `B^2-4AS` . B is our 5 its the one that has the x but not in any form of power so we want our x not to be an exponential. The A is our 3 which is the one that is exponential. And our S is the standard number which is -2 in this case. So by using the formula we have : `5^2-4*3*-2=1`
Now we are going to use another the next part of the mathematical formula `-5+sqrt1=Q =>Q/6` and our next formula for the second solution `-5-sqrt1=N=>N/6`
So our answers are `x1=-4/6` and `x2=-1`
with x1 and x2 being the solutions.