How to find instantaneous rate of change for #f(x)=x^3-x^2-2x 4# at x=2? Calculus Derivatives Instantaneous Rate of Change at a Point 1 Answer mizoo May 24, 2018 #f'(2)=6# Explanation: #f(x) =x^3 -x^2-2x+or-4# #f'(x) =3x^2-2x-2# #f'(2)=12-4-2=6# Answer link Related questions How do you find the instantaneous rate of change of a function at a point? What is Instantaneous Rate of Change at a Point? How do you estimate instantaneous rate of change at a point? How do you find the instantaneous rate of change of #f (x)= x ^2 +2 x ^4# at #x=1#? How do you find the instantaneous rate of change of #f(t)=(2t^3-3t+4)# when #t=2#? How do you find the instantaneous rate of change of #w# with respect to #z# for #w=1/z+z/2#? Can instantaneous rate of change be zero? Can instantaneous rate of change be negative? How do you find the instantaneous rate of change at a point on a graph? How does instantaneous rate of change differ from average rate of change? See all questions in Instantaneous Rate of Change at a Point Impact of this question 1455 views around the world You can reuse this answer Creative Commons License