Question

How do you find the derivative of `e^sinx`?

Answer 1

`y'=e^sin(x)*cos(x)`

Explanation:

Taking the logarithm on both sides we get
`ln(y)=sin(x)`
Differentiating this with respect to `x`:
`1/y*y'=cos(x)`
so
`y'=e^(sin(x))*cos(x)`