How do you multiply #3x(5x^2-x+4)#?

1 Answer
May 25, 2018

#15x^3-3x^2+12x#

Explanation:

We need to distribute the #3x# to all terms in the parenthesis. We essentially have

#color(blue)(3x)(5x^2)-color(blue)(3x)(x)+color(blue)(3x)(4)#

Notice, the #3x# is being multiplied by all terms. We get

#bar(ul(|color(white)(2/2)15x^3-3x^2+12xcolor(white)(2/2)|))#

as our final answer.

Hope this helps!