Why do rates of reaction change with pH?
1 Answer
Do they really?
A counterexample is:
#"N"_2"O"_4(g) rightleftharpoons 2"NO"_2(g)#
The forward reaction has a rate constant of
The forward reaction is first-order, with a rate law of:
#r_(fwd)(t) = k_(fwd)["N"_2"O"_4]#
The reverse reaction is second-order, with a rate law of:
#r_(rev)(t) = k_(rev)["NO"_2]^2#
Clearly, no
Thus, the reaction is completely