Why do rates of reaction change with pH?
1 Answer
May 25, 2018
Do they really?
A counterexample is:
"N"_2"O"_4(g) rightleftharpoons 2"NO"_2(g)
The forward reaction has a rate constant of
The forward reaction is first-order, with a rate law of:
r_(fwd)(t) = k_(fwd)["N"_2"O"_4]
The reverse reaction is second-order, with a rate law of:
r_(rev)(t) = k_(rev)["NO"_2]^2
Clearly, no
Thus, the reaction is completely