Question

Oxygen gas is at STP when it occupies a volume 5.5 liters. To what temperature should it be raised to occupy a volume of 9.0 liters?

Answer 1

Well...for a given quantity of gas (such as we gots here)….

`VpropT`

Explanation:

And this is old `"Charles' Law..."`

Now `"STP"` specifies (depending on your syllabus) `298*K` and (near to) `1*atm`...

Given `VpropT`, `V=kT`...solving for `k`, `k=V/T`...but this should apply at all temperatures for a given quantity of gas...and so...

`V_1/T_1=V_2/T_2`...and we solve for `T_2=(V_2xxT_1)/V_1`

`-=(9.0*Lxx273.15*K)/(5.5*L)=447.0*K-=173.8` `""^@C`