How do you solve the system of equations #x+ 3y = - 14# and #2x - 4y = 30#?
1 Answer
May 26, 2018
Explanation:
#x+3y=-14to(1)#
#2x-4y=30to(2)#
#"rearrange equation "(1)" expressing x in terms of y"#
#x=-14-3yto(3)#
#"substitute "x=-14-3y" into equation "(2)#
#2(-14-3y)-4y=30larrcolor(blue)"distribute"#
#-28-6y-4y=30larrcolor(blue)"simplify"#
#-28-10y=30#
#"add 28 to both sides"#
#-10y=58#
#"divide both sides by "-10#
#y=58/(-10)=-29/5#
#"substitute this value into equation "(3)" for x"#
#x=-14-(3xx-29/5)=-70/5+87/5=17/5#
#"solution is "(x,y)to(17/5,-29/5)#