Please solve q107 ?

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1 Answer
May 26, 2018

#|AFD|=4 " units"^2#

Explanation:

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Let #|ABC|# denote area of #ABC#
Given #BE=EC, and |ABC|=48#
#=> |ABE|=|AEC|=48/2=24#
given #AF=FE#,
#=> |BAF|=|BEF|=24/2=12#
draw a line joining #D andE#, as shown in the figure.
let #|AFD|=a, => |FED|=a#
#=> |DEC|=|AEC|-|AED|=24-2a#
as #|DBE|=|DEC|, => 12+a=24-2a, => a=4#
Hence, #|AFD|=a=4 " units"^2#