Question

How do you solve the following system?: `-2x+3y=5, x+3y=6`

Answer 1

`x=1/3, y=17/9`

Explanation:

`-2x+3y=5` (assign no. (1))
`x+3y=6` (assign no. (2))

From (2),
`x=6-3y`

Substitute (2) into (1)
`-2(6-3y)+3y=5`
`-12+6y+3y=5`
`9y=17`
`y=17/9`

Substitute `y=17/9` into (2)
`x=6-3(17/9)`
`x=6-(51/9)`
`x=3/9`
`x=1/3`

Therefore, `x=1/3`, `y=17/9`