Question

How do you solve for a in `5 + ab = c`?

Answer 1

`a=(c-5)/b`

Explanation:

`"isolate "ab" by subtracting 5 from both sides"`

`cancel(5)cancel(-5)+ab=c-5`

`ab=c-5`

`"divide both sides by "b`

`(a cancel(b))/cancel(b)=(c-5)/brArra=(c-5)/b`

Answer 2

`a = (c - 5)/b`

Explanation:

As there are 3 variables in this equation, i.e `a`, `b` and `c`.

Therefore, the value of `a` would be in terms of `b` and `c`.

Now, as per the question, we have

`5 + ab = c`

`:. ab = c - 5`

`:. a = (c - 5)/b`

Hence the value of `a` in terms of `b` and `c` is `(c - 5)/b`.

Answer 3

`color(blue)(5+ab=c`

To, find a, we need to isolate it in the left hand side of the equation.

We can do that by adding or subtracting or multiplying or dividing the same number on both sides of the equation

So, subtract `5` from both sides

`rarrcancel5+ab-cancel5=c-5`

`rarrab=c-5`

Divide both sides by `b`

`rarr(acancelb)/cancelb=(c-5)/b`

`color(green)(rArra=(c-5)/b`

Hope that helps.... `phi`