How do you write the standard equation for the circle center (–6, 7), r = 9?

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Answer 1 · 2018-05-26T13:59:57

#(x+6)^2 + (y - 7)^2 = 81#

Standard equation for a circle is:

#(x-h)^2 + (y - k)^2 = r^2#

#r = radius = 9#

#(h,k) =(-6,7)# is the shift from #(0,0)#

#(x-(-6))^2 + (y - 7)^2 = 9^2#

#(x+6)^2 + (y - 7)^2 = 81#

graph{(x+6)^2 + (y - 7)^2 = 81 [-22.33, 17.67, -3.12, 16.88]}