Question

Does `a_n=x^n/n^x` converge for any x?

Answer 1

`"No"`

Explanation:

`"If "x = -1", we have "a_n = n*(-1)^n" and this alternates"`
`"between "-oo" and "+oo" for "n->oo, " depending on the"`
`"fact if n is odd or even."`
`"If "x < -1", the situation gets even worse."`
`"There is only convergence for "x > -1.`