What is x if #3x+2(x+5)^2=15#?

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Answer 1 · 2018-05-28T15:27:45

#x=-23/4+-sqrt(249/4)#

#3x+2(x+5)^2=15#

#3x+2(x+5)(x+5)=15#

FOIL

#3x+2(x^2 + 10x +25)=15#

Distribute the 2

#3x+2x^2 + 20x +50=15#

Combine like terms:

#2x^2 + 23x +35=0#

you will need to use the quadratic formula to solve the roots:

#x=(-b+-sqrt(b^2 - 4ac))/(2a)#

a=2
b=23
c=35

#x=-23/4+-sqrt(249/4)#