How do you find the equation of the line tangent to f(x) = 6x^2 - 1 at x = 3?
1 Answer
May 28, 2018
Explanation:
The equation of the tangent line at
graph{(y-6x^2+1)(y-36x+55)=0 [-41.1, 41.1, -20.55, 20.55]}