How do you solve #3( 2x + 3x + 2) = - 4x + 124#?

1 Answer
Echxo · Stefan V.
May 28, 2018

#x = 118/19#

Explanation:

First, expand by multiplying #3# by every term in the brackets. Then group together the terms with #x# in them and group the terms without #x#s in them together.

Finally, divide the number in front of the #x# by the number on the other side to solve for #x#.

#3 (2x + 3x + 2) = -4x + 124#

#3*2x + 3*3x + 3*2 = -4x + 124#

#6x + 9x + 6 = -4x + 124#

#15x + 6 = -4x + 124#

#15x + 4x = 124 - 6#

#19x = 118#

#x = 118/19 = 6.21#

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