How do you graph the function #y=-5x+1#?

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Answer 1 · 2018-05-28T22:50:05

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (-5 * 0) + 1#

#y = 0 + 1#

#y = 1# or #(0, 1)#

Second Point: For #x = 1#

#y = (-5 * 1) + 1#

#y = -5 + 1#

#y = -4# or #(1, -4)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-1)^2-0.035)((x-1)^2+(y+4)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+5x-1)(x^2+(y-1)^2-0.035)((x-1)^2+(y+4)^2-0.035)=0 [-10, 10, -5, 5]}